Question

1. if an average - sized guy drank a beer as fast as possible, what would be his bac (blood alcohol content)? assume that he contains 5000 ml of blood and that one can of beer has 15 g of alcohol, and ignore the facts that it takes time for alcohol to be absorbed into the bloodstream and that it gets metabolized. hint: bac is given in grams (g) of alcohol per 100 ml of blood (not g/ml).

Explanation:

Step1: Identify given values

We know:

• Amount of alcohol (\(m_{alcohol}\)) = 15 g (from one beer)
• Volume of blood (\(V_{blood}\)) = 5000 mL
• BAC is grams of alcohol per 100 mL of blood.

Step2: Calculate BAC

First, find out how much alcohol is in 100 mL of blood.
Let \(x\) be the amount of alcohol in 100 mL of blood.
We can set up a proportion:
\(\frac{m_{alcohol}}{V_{blood}}=\frac{x}{100\ mL}\)
Substitute the known values:
\(\frac{15\ g}{5000\ mL}=\frac{x}{100\ mL}\)
Solve for \(x\):
\(x=\frac{15\ g\times100\ mL}{5000\ mL}\)
\(x = \frac{1500}{5000}\ g\)
\(x=0.3\ g\) (per 100 mL of blood)

Answer:

The BAC (Blood Alcohol Content) is \(0.3\) grams of alcohol per 100 mL of blood (or \(0.003\) g/mL, but in the context of BAC, it's often expressed as g/100 mL, so \(0.3\) g/100 mL).