Question

h) p + 5(p - 4) = 148
m=52

1. -52

6p=148 +20
6p=168
p=28
28+
33
3
j) 2z - 4(z - 3) = 10

Explanation:

Part h: Solve \( p + 5(p - 4) = 148 \)

Step 1: Expand the bracket

Using the distributive property \( a(b - c)=ab - ac \), we expand \( 5(p - 4) \) to get \( 5p-20 \). So the equation becomes:
\( p + 5p-20=148 \)

Step 2: Combine like terms

Combine \( p \) and \( 5p \) to get \( 6p \). The equation is now:
\( 6p-20 = 148 \)

Step 3: Add 20 to both sides

To isolate the term with \( p \), we add 20 to both sides of the equation:
\( 6p-20 + 20=148 + 20 \)
\( 6p=168 \)

Step 4: Divide by 6

Divide both sides by 6 to solve for \( p \):
\( p=\frac{168}{6} \)
\( p = 28 \)

Part j: Solve \( 2z-4(z - 3)=10 \)

Step 1: Expand the bracket

Using the distributive property \( a(b - c)=ab - ac \), we expand \( - 4(z - 3) \) to get \( -4z + 12 \). So the equation becomes:
\( 2z-4z + 12=10 \)

Step 2: Combine like terms

Combine \( 2z \) and \( - 4z \) to get \( -2z \). The equation is now:
\( -2z+12 = 10 \)

Step 3: Subtract 12 from both sides

To isolate the term with \( z \), we subtract 12 from both sides of the equation:
\( -2z+12-12=10 - 12 \)
\( -2z=-2 \)

Step 4: Divide by - 2

Divide both sides by - 2 to solve for \( z \):
\( z=\frac{-2}{-2} \)
\( z = 1 \)

Answer:

s:

• For \( p + 5(p - 4)=148 \), \( p=\boldsymbol{28} \)
• For \( 2z-4(z - 3)=10 \), \( z=\boldsymbol{1} \)