Question

a 1451 kg car is traveling at 48.0 km/h. how much kinetic energy does it possess? k.e. = 1.28 x 10^5 j 3.48 x 10^5 j 9.65 x 10^5 j 1.67 x 10^5 j

Explanation:

Step1: Convertir la velocidad a m/s

$$v = 48.0\,\frac{km}{h}\times\frac{1000\,m}{1\,km}\times\frac{1\,h}{3600\,s}=\frac{48000}{3600}\,m/s = 13.33\,\frac{m}{s}$$

Step2: Calcular la energía cinética

La fórmula de la energía cinética es $K.E.=\frac{1}{2}mv^{2}$, donde $m = 1451\,kg$ y $v = 13.33\,\frac{m}{s}$
$$K.E.=\frac{1}{2}\times1451\times(13.33)^{2}$$
$$K.E. = 725.5\times177.6889$$
$$K.E. = 128,973.3\approx1.29\times10^{5}\,J$$

Answer:

$1.28\times10^{5}\,J$