Question

if a 13.9 g object has a specific heat of 1.31 j/(g°c) and it experiences a temperature increase from 55.0°c to 67.5°c, how much heat in joules did it absorb?

• your answer should have three significant figures. (round your answer to an integer.)
• do not include units in your answer.

Explanation:

Step1: Calculate the temperature change

$\Delta T=T_{final}-T_{initial}=67.5 - 55.0=12.5^{\circ}C$

Step2: Use the heat - absorption formula

The formula for heat absorption is $Q = mc\Delta T$, where $m = 13.9$ g, $c=1.31\frac{J}{g^{\circ}C}$, and $\Delta T = 12.5^{\circ}C$.
Substitute the values into the formula: $Q=13.9\times1.31\times12.5$.
First, calculate $13.9\times1.31 = 18.209$.
Then, $Q=18.209\times12.5=227.6125$.
Rounding to three significant figures gives $229$.

Answer:

229