Question

1. how much energy is required to raise the temperature of 345.34g of aluminum from 35.0°c to 250.0°c? the specific heat of aluminum is 0.90 j/g°c.

Explanation:

Step1: Calculate the temperature change

$\Delta T=T_{final}-T_{initial}=250.0 - 35.0=215.0^{\circ}C$

Step2: Use the heat formula

The formula for heat $Q = mc\Delta T$, where $m = 345.34g$, $c=0.90J/g^{\circ}C$, and $\Delta T = 215.0^{\circ}C$.
Substitute the values: $Q=345.34\times0.90\times215.0$
First, $345.34\times0.90 = 310.806$
Then, $310.806\times215.0=66823.29J$

Answer:

$66823.29J$