Question

1. al + s₈ → __ al₂s₃

balancing chemical equations
i

1. cs + n₂ → __ cs₃n
2. mg + cl₂ → __ mgcl₂
3. rb + rbno₃ → rb₂o + n₂

Explanation:

Step1: Balance sulfur atoms

In \(S_8\) and \(Al_2S_3\), to balance sulfur, we find the least - common multiple of \(8\) and \(3\). The LCM of \(8\) and \(3\) is \(24\). So we set the coefficient of \(S_8\) as \(3\) (\(3\times8 = 24\)) and the coefficient of \(Al_2S_3\) as \(8\) (\(8\times3=24\)).

Step2: Balance aluminum atoms

Since the coefficient of \(Al_2S_3\) is \(8\), for aluminum atoms (\(Al\)), the coefficient of \(Al\) should be \(16\) (because in \(Al_2S_3\), there are \(2\) \(Al\) atoms per formula unit, and \(8\times2 = 16\)).

The balanced equation is \(16Al+3S_8 = 8Al_2S_3\)

Answer:

\(16Al+3S_8 = 8Al_2S_3\)