Question

12 charity is sledding down a snowy hill. when she begins her slide at the top of the hill, she has a velocity of 2.2 m/s north. she slides down the hill for 4.1 seconds, and when she reaches the bottom she has a velocity of 5.9 m/s. how far did charity sled during this 4.1 second period? 17 meters 33 meters 4.5 meters 12 meters

Explanation:

Step1: Find the average velocity

The formula for average velocity \(v_{avg}=\frac{v_{i} + v_{f}}{2}\), where \(v_{i}\) is the initial velocity and \(v_{f}\) is the final velocity.
Given \(v_{i}=2.2\ m/s\) and \(v_{f}=5.9\ m/s\), then \(v_{avg}=\frac{2.2 + 5.9}{2}=\frac{8.1}{2}=4.05\ m/s\)

Step2: Calculate the distance

The formula for distance \(d=v_{avg}\times t\), where \(t\) is the time.
Given \(t = 4.1\ s\) and \(v_{avg}=4.05\ m/s\), then \(d=4.05\times4.1 = 16.605\approx17\ m\)

Answer:

17 meters