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12. $x^{2}+3x - 10$ $x^{2}+x - 6$ 13. $\frac{1}{x - 4}-\frac{1}{x}$

Question

  1. $x^{2}+3x - 10$ $x^{2}+x - 6$
  2. $\frac{1}{x - 4}-\frac{1}{x}$

Explanation:

Step1: Find a common denominator

The common denominator of \(x - 4\) and \(x\) is \(x(x - 4)\).

Step2: Rewrite the fractions with the common denominator

\(\frac{1}{x - 4}-\frac{1}{x}=\frac{x}{x(x - 4)}-\frac{x - 4}{x(x - 4)}\)

Step3: Subtract the numerators

\(\frac{x-(x - 4)}{x(x - 4)}=\frac{x - x+4}{x(x - 4)}=\frac{4}{x(x - 4)}\)

Answer:

\(\frac{4}{x(x - 4)}\)