Question

1. simplify: $(3x^{2}y^{4})(6x^{-3}y^{2}) / (2x^{-1}y^{3})$

a. $9y^{3}$
b. $9x^{0}y^{3}$
c. $9y^{3}/x$
d. $9x^{3}$

Explanation:

Step1: Multiply coefficients

$3×6 = 18$

Step2: Combine x terms

$x^{2}×x^{-3} = x^{-1}$

Step3: Combine y terms

$y^{4}×y^{2} = y^{6}$

Step4: Divide by denominator coefficient

$18÷2 = 9$

Step5: Divide x terms

$x^{-1}÷x^{-1} = x^{0} = 1$

Step6: Divide y terms

$y^{6}÷y^{3} = y^{3}$

Step7: Combine results

$9×1×y^{3} = 9y^{3}$

Answer:

A. 9y³