Question

1. how many orbitals are in the following sublevels?

a) 3p sublevel =
b) 2s sublevel =
c) 4p sublevel =
d) 3d sublevel =
e) 4f sublevel =

1. differentiate between an orbit and an orbital.
2. draw the 2s and 2px orbital.

Explanation:

Step1: Recall the formula for number of orbitals in a sub - level

The number of orbitals in a sub - level is given by \(2l + 1\), where \(l\) is the azimuthal quantum number.

• For \(s\) sub - level, \(l = 0\). So the number of orbitals \(=2(0)+1=1\)
• For \(p\) sub - level, \(l = 1\). So the number of orbitals \(=2(1)+1 = 3\)
• For \(d\) sub - level, \(l=2\). So the number of orbitals \(=2(2)+1 = 5\)
• For \(f\) sub - level, \(l = 3\). So the number of orbitals \(=2(3)+1=7\)

Step2: Apply the formula to each sub - level

• a) For \(3p\) ( \(p\) sub - level, \(l = 1\) ), number of orbitals \(=3\)
• b) For \(2s\) ( \(s\) sub - level, \(l = 0\) ), number of orbitals \(=1\)
• c) For \(4p\) ( \(p\) sub - level, \(l = 1\) ), number of orbitals \(=3\)
• d) For \(3d\) ( \(d\) sub - level, \(l = 2\) ), number of orbitals \(=5\)
• e) For \(4f\) ( \(f\) sub - level, \(l = 3\) ), number of orbitals \(=7\)

Answer:

a) \(3\)
b) \(1\)
c) \(3\)
d) \(5\)
e) \(7\)