Question

1. a 40 kg cart is pushed with a 200 n force. if friction is 40 n, what is the acceleration?
2. a 20 kg box is pulled with 60 n, but friction opposes motion with 20 n. find the acceleration.
3. a 2,000 kg truck accelerates at 1.5 m/s². what net force acts on the truck?
4. a 0.25 kg baseball is hit with a force of 20 n. what acceleration does it experience?
5. a 70 kg skateboarder accelerates down a hill at 1.2 m/s². find the net force acting on the skateboarder.
6. a 3 kg cart is pushed by a 20 n force while friction is 2 n. determine its acceleration.

Explanation:

Step1: Calculate net force

According to Newton's second law \(F = ma\), first find the net force \(F_{net}\). For the problem of the cart (\(m = 40\space kg\), \(F_{applied}=200\space N\), \(F_{friction} = 40\space N\)), \(F_{net}=F_{applied}-F_{friction}\).
\(F_{net}=200 - 40=160\space N\)

Step2: Calculate acceleration

Use the formula \(a=\frac{F_{net}}{m}\). Substitute \(F_{net} = 160\space N\) and \(m = 40\space kg\) into the formula.
\(a=\frac{160}{40}=4\space m/s^{2}\)

Answer:

\(4\space m/s^{2}\)