Question

in 11-14, tell how many terms each expression has.

1. $4c + 7\frac{1}{2}$
2. $80.6 - 3p - q$
3. $(7 \cdot 2) \div s$
4. $100 + (8 \cdot 6) - 50 + 2$

Explanation:

Problem 11: \(4c + 7\frac{1}{2}\)

Step 1: Identify terms

A term is a number, a variable, or a product/quotient of numbers and variables separated by addition or subtraction. In \(4c + 7\frac{1}{2}\), the operations are addition. So we separate by the plus sign. The first term is \(4c\) (a product of 4 and \(c\)) and the second term is \(7\frac{1}{2}\) (a constant). So there are 2 terms.

Problem 12: \(80.6 - 3p - q\)

Step 1: Identify terms

Terms are separated by subtraction (which is addition of the opposite). So we can rewrite the expression as \(80.6+(- 3p)+(-q)\). Now, separating by addition signs, the terms are \(80.6\), \(-3p\), and \(-q\). So there are 3 terms.

Problem 13: \((7\cdot2)\div s\)

Step 1: Simplify the numerator (optional)

First, calculate \(7\cdot2 = 14\), so the expression becomes \(\frac{14}{s}\) (or \(14\div s\)). A term can also be a quotient. Here, the entire expression is a single quotient of 14 and \(s\), so there is 1 term.

Problem 14: \(100+(8\cdot6)-50 + 2\)

Step 1: Simplify the product (optional)

First, calculate \(8\cdot6=48\), so the expression becomes \(100 + 48-50 + 2\). Now, separate by addition and subtraction. Rewrite subtraction as addition of opposites: \(100+48+(- 50)+2\). The terms are \(100\), \(48\), \(-50\), and \(2\). So there are 4 terms.

Answer:

s:

1. 2 terms
2. 3 terms
3. 1 term
4. 4 terms