Question

1. $4y - x = -2$; $y = 1$
2. $y = 4x - 2$; $x = -1$
3. $4x - 3y = 18$; $x = 3$

Explanation:

Problem 9:

Step1: Substitute \( y = 1 \) into the equation \( 4y - x = -2 \)

\( 4(1) - x = -2 \)

Step2: Simplify and solve for \( x \)

\( 4 - x = -2 \)
Subtract 4 from both sides: \( -x = -2 - 4 = -6 \)
Multiply both sides by -1: \( x = 6 \)

Step1: Substitute \( x = -1 \) into the equation \( y = 4x - 2 \)

\( y = 4(-1) - 2 \)

Step2: Simplify to find \( y \)

\( y = -4 - 2 = -6 \)

Step1: Substitute \( x = 3 \) into the equation \( 4x - 3y = 18 \)

\( 4(3) - 3y = 18 \)

Step2: Simplify and solve for \( y \)

\( 12 - 3y = 18 \)
Subtract 12 from both sides: \( -3y = 18 - 12 = 6 \)
Divide both sides by -3: \( y = \frac{6}{-3} = -2 \)

Answer:

\( x = 6 \)

Problem 11: