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Question
- \\(\frac{7x}{15} - \frac{4x}{15}\\)
- \\(\frac{2}{n} - \frac{6}{n}\\)
- \\(\frac{2x}{3} - \frac{x - 1}{3}\\)
- \\(\frac{3a}{10} - \frac{5a + 1}{10}\\)
- \\(\frac{x + 3}{4} - \frac{9x + 11}{4}\\)
- \\(\frac{2}{x + 3} + \frac{5}{x + 3}\\)
- \\(\frac{x}{x - 2} + \frac{1}{x - 2}\\)
- \\(\frac{n}{n - 2} - \frac{3n - 1}{n - 2}\\)
- \\(\frac{5}{4y - 1} - \frac{3}{1 - 4y}\\)
- \\(\frac{5c}{c - d} + \frac{5d}{d - c}\\)
- \\(\frac{2}{x} + \frac{3}{x^2}\\)
- \\(\frac{8}{ab} - \frac{6}{ab^2}\\)
- \\(\frac{4}{3xy} + \frac{3}{2x^2}\\)
- \\(\frac{4}{5(x + 1)} + \frac{x}{x + 1}\\)
- \\(\frac{1 + 2x}{4} + \frac{1 + 2x}{6}\\)
- \\(\frac{5b + 2}{8} + \frac{3b - 4}{16}\\)
- \\(\frac{a - 6}{15} + \frac{4 - a}{10}\\)
- \\(\frac{5n - 2}{12} - \frac{3(n - 3)}{8}\\)
- \\(\frac{4x + 3}{3} - \frac{7x}{4} + \frac{x - 3}{6}\\)
- \\(\frac{2m}{5} - \frac{m + 4}{4} + \frac{2 - m}{10}\\)
Let's solve problem 2: \(\frac{7x}{15}-\frac{4x}{15}\)
Step 1: Subtract the numerators
Since the denominators are the same, we subtract the numerators: \(\frac{7x - 4x}{15}\)
Step 2: Simplify the numerator
Simplify \(7x - 4x\) to get \(3x\), so we have \(\frac{3x}{15}\)
Step 3: Simplify the fraction
Divide numerator and denominator by 3: \(\frac{x}{5}\)
Now problem 3: \(\frac{2}{n}-\frac{6}{n}\)
Step 1: Subtract the numerators
Same denominator, so \(\frac{2 - 6}{n}\)
Step 2: Simplify the numerator
\(2 - 6 = -4\), so \(\frac{-4}{n}\) or \(-\frac{4}{n}\)
Problem 5: \(\frac{2x}{3}-\frac{x - 1}{3}\)
Step 1: Subtract the numerators
\(\frac{2x-(x - 1)}{3}\)
Step 2: Simplify the numerator
Distribute the negative sign: \(2x - x + 1 = x + 1\), so \(\frac{x + 1}{3}\)
Problem 6: \(\frac{3a}{10}-\frac{5a + 1}{10}\)
Step 1: Subtract the numerators
\(\frac{3a-(5a + 1)}{10}\)
Step 2: Simplify the numerator
\(3a - 5a - 1 = -2a - 1\), so \(\frac{-2a - 1}{10}\) or \(-\frac{2a + 1}{10}\)
Problem 8: \(\frac{x + 3}{4}-\frac{9x + 11}{4}\)
Step 1: Subtract the numerators
\(\frac{(x + 3)-(9x + 11)}{4}\)
Step 2: Simplify the numerator
\(x + 3 - 9x - 11 = -8x - 8\), factor out -8: \(-8(x + 1)\), so \(\frac{-8(x + 1)}{4} = -2(x + 1) = -2x - 2\)
Problem 9: \(\frac{2}{x + 3}+\frac{5}{x + 3}\)
Step 1: Add the numerators
Same denominator, so \(\frac{2 + 5}{x + 3}\)
Step 2: Simplify the numerator
\(2 + 5 = 7\), so \(\frac{7}{x + 3}\)
Problem 11: \(\frac{x}{x - 2}+\frac{1}{x - 2}\)
Step 1: Add the numerators
\(\frac{x + 1}{x - 2}\)
Problem 12: \(\frac{n}{n - 2}-\frac{3n - 1}{n - 2}\)
Step 1: Subtract the numerators
\(\frac{n-(3n - 1)}{n - 2}\)
Step 2: Simplify the numerator
\(n - 3n + 1 = -2n + 1\), so \(\frac{-2n + 1}{n - 2}\) or \(\frac{1 - 2n}{n - 2}\)
Problem 14: \(\frac{5}{4y - 1}-\frac{3}{1 - 4y}\)
Step 1: Rewrite the second denominator
Notice that \(1 - 4y = -(4y - 1)\), so \(\frac{3}{1 - 4y} = -\frac{3}{4y - 1}\)
Step 2: Subtract
\(\frac{5}{4y - 1}-(-\frac{3}{4y - 1}) = \frac{5 + 3}{4y - 1} = \frac{8}{4y - 1}\)
Problem 15: \(\frac{5c}{c - d}+\frac{5d}{d - c}\)
Step 1: Rewrite the second denominator
\(d - c = -(c - d)\), so \(\frac{5d}{d - c} = -\frac{5d}{c - d}\)
Step 2: Add
\(\frac{5c}{c - d}-\frac{5d}{c - d} = \frac{5c - 5d}{c - d}\)
Step 3: Factor the numerator
Factor out 5: \(\frac{5(c - d)}{c - d} = 5\) (assuming \(c
eq d\))
Problem 17: \(\frac{2}{x}+\frac{3}{x^2}\)
Step 1: Find a common denominator
The common denominator is \(x^2\), so rewrite \(\frac{2}{x}\) as \(\frac{2x}{x^2}\)
Step 2: Add the fractions
\(\frac{2x}{x^2}+\frac{3}{x^2} = \frac{2x + 3}{x^2}\)
Problem 18: \(\frac{8}{ab}-\frac{6}{ab^2}\)
Step 1: Find a common denominator
Common denominator is \(ab^2\), rewrite \(\frac{8}{ab}\) as \(\frac{8b}{ab^2}\)
Step 2: Subtract the fractions
\(\frac{8b}{ab^2}-\frac{6}{ab^2} = \frac{8b - 6}{ab^2}\)
Step 3: Factor the numerator
Factor out 2: \(\frac{2(4b - 3)}{ab^2}\)
Problem 20: \(\frac{4}{3xy}+\frac{3}{2x^2}\)
Step 1: Find a common denominator
Common denominator is \(6x^2y\), rewrite \(\frac{4}{3xy}\) as \(\frac{8x}{6x^2y}\) and \(\frac{3}{2x^2}\) as \(\frac{9y}{6x^2y}\)
Step 2: Add the fractions
\(\frac{8x + 9y}{6x^2y}\)
Problem 21: \(\frac{4}{5(x + 1)}+\frac{x}{x + 1}\)
Step 1: Find a common denominator
Common denominator is \(5(x + 1)\), rewrite \(\frac{x}{x + 1}\) as \(\frac{5x}{5(x + 1)}\)
Step 2: Add the fractions
\(\frac{4 + 5x}{5(x + 1)}\) or \(\frac{5x + 4}{5(x + 1)}\)
Problem 23: \(\frac{1 + 2x}{4}+\frac{1 + 2x}{6}\)
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s:
- \(\boldsymbol{\frac{x}{5}}\)
- \(\boldsymbol{-\frac{4}{n}}\)
- \(\boldsymbol{\frac{x + 1}{3}}\)
- \(\boldsymbol{-\frac{2a + 1}{10}}\)
- \(\boldsymbol{-2x - 2}\)
- \(\boldsymbol{\frac{7}{x + 3}}\)
- \(\boldsymbol{\frac{x + 1}{x - 2}}\)
- \(\boldsymbol{\frac{1 - 2n}{n - 2}}\)
- \(\boldsymbol{\frac{8}{4y - 1}}\)
- \(\boldsymbol{5}\) (for \(c
eq d\))
- \(\boldsymbol{\frac{2x + 3}{x^2}}\)
- \(\boldsymbol{\frac{2(4b - 3)}{ab^2}}\)
- \(\boldsymbol{\frac{8x + 9y}{6x^2y}}\)
- \(\boldsymbol{\frac{5x + 4}{5(x + 1)}}\)
- \(\boldsymbol{\frac{5(1 + 2x)}{12}}\)
- \(\boldsymbol{\frac{13b}{16}}\)
- \(\boldsymbol{-\frac{a}{30}}\)
- \(\boldsymbol{\frac{n + 23}{24}}\)
- \(\boldsymbol{\frac{2 - x}{4}}\)
- \(\boldsymbol{\frac{m - 16}{20}}\)