Question

if 102.7 g of tin is mixed with 10.9 g of copper to create the alloy pewter, how many moles of metal are present in the pewter? 1.037 mol total 0.8675 mol total 0.9643 mol total 1.604 mol total 0.6233 mol total

Explanation:

Step1: Calculate moles of tin

Use the formula \(n=\frac{m}{M}\), where \(m = 102.7\space g\) (mass of tin), \(M=118.71\space g/mol\) (molar mass of tin).
\(n_{Sn}=\frac{102.7}{118.71}\approx0.865\space mol\)

Step2: Calculate moles of copper

Use the formula \(n=\frac{m}{M}\), where \(m = 10.9\space g\) (mass of copper), \(M = 63.55\space g/mol\) (molar mass of copper).
\(n_{Cu}=\frac{10.9}{63.55}\approx0.172\space mol\)

Step3: Calculate total moles

\(n_{total}=n_{Sn}+n_{Cu}\)
\(n_{total}=0.865 + 0.172=1.037\space mol\)

Answer:

1.037 mol total