Question

q.4. 100g of ethanol at 25°c is heated until it reaches 50°c. how much heat does the ethanol gain? (ans. 6.02×10³j)

Explanation:

Step1: Identify the formula

The formula for heat \(Q = mc\Delta T\), where \(m\) is mass, \(c\) is specific heat capacity, \(\Delta T\) is temperature change.

Step2: Determine the values

For ethanol, \(c = 2.44\space J/g^{\circ}C\), \(m = 100\space g\), \(\Delta T=T_{final}-T_{initial}=50 - 25=25^{\circ}C\)

Step3: Substitute values into formula

\(Q=(100\space g)\times(2.44\space J/g^{\circ}C)\times(25^{\circ}C)\)
\(Q = 100\times2.44\times25\space J\)
\(Q=6100\space J = 6.1\times 10^{3}\space J\) (close to the given answer \(6.02\times 10^{3}\space J\) considering possible rounding differences in specific - heat value used in source)

Answer:

\(6.1\times 10^{3}\space J\)