Question

1. a 10 kg object experiences an acceleration of 2 m/. what force was applied to the object?

Explanation:

Step1: Recall Newton's second law

Newton's second law is \(F = ma\), where \(F\) is force, \(m\) is mass, and \(a\) is acceleration.

Step2: Substitute the given values

Given \(m = 10\space kg\) and \(a=2\space m/s^{2}\). Substitute into \(F = ma\): \(F=(10\space kg)\times(2\space m/s^{2})\)

Step3: Calculate the force

\(F = 20\space N\)

Answer:

\(20\space N\)