Question

1. due to the law of conservation of matter, how many grams of carbon dioxide (co₂) are formed in the reaction?

ch₄ + 2o₂ → co₂ + 2h₂o
32 grams + 28 grams → + 35 grams
a. 25g
b. 32g
c. 60g
d. 35g

1. which equation represents the law of conservation of matter?

a. h₂ + o₂ → h₂o
b. na + cl₂ → nacl
c. 2na + o₂ → 2nao
d. fes + 2hcl → fecl + 2h₂s

Explanation:

Step1: Apply the Law of Conservation of Matter

According to the Law of Conservation of Matter, the mass of reactants equals the mass of products.
The mass of reactants: \(32 + 28=60\) grams.
The mass of products: mass of \(CO_{2}\)+ \(35\) grams.

Step2: Calculate the mass of \(CO_{2}\)

Let the mass of \(CO_{2}\) be \(x\). Then \(x + 35=60\).
Solving for \(x\): \(x=60 - 35\).

Answer:

A. \(25\)g