Question

a. $x^2 + 10 = 60$

• 10 -10

$x^2 = \sqrt{50}$
$x = \pm 5\sqrt{2}$
b. (x
$\sqrt{(x - 3)}$

Explanation:

Step1: Solve for \(x^2\)

Subtract 10 from both sides of the equation \(x^2 + 10 = 60\).
\(x^2 + 10 - 10 = 60 - 10\)
\(x^2 = 50\)

Step2: Solve for \(x\)

Take the square root of both sides.
\(\sqrt{x^2} = \sqrt{50}\)
Simplify \(\sqrt{50}\) as \(\sqrt{25 \times 2} = 5\sqrt{2}\), and recall that \(\sqrt{x^2} = \pm x\).
So, \(x = \pm 5\sqrt{2}\)

Answer:

The solution to the equation \(x^2 + 10 = 60\) is \(x = \pm 5\sqrt{2}\) (or approximately \(x \approx \pm 7.07\) if a decimal approximation is preferred).