Question

2.06 mol c₂h₄
molecules
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0.968 mol n₂o
molecules

Explanation:

Step1: Recall Avogadro's number

Avogadro's number \(N_A = 6.022\times10^{23}\text{ molecules/mol}\).

Step2: Calculate the number of \(C_2H_4\) molecules

Use the formula \(N = n\times N_A\), where \(n = 2.06\space mol\).
\(N_{C_2H_4}=2.06\space mol\times6.022\times 10^{23}\space\text{molecules/mol}\)
\(N_{C_2H_4}=2.06\times6.022\times10^{23}\)
\(N_{C_2H_4}=1.24\times10^{24}\space\text{molecules}\)

Step3: Calculate the number of \(N_2O\) molecules

Use the formula \(N = n\times N_A\), where \(n = 0.968\space mol\)
\(N_{N_2O}=0.968\space mol\times6.022\times 10^{23}\space\text{molecules/mol}\)
\(N_{N_2O}=0.968\times6.022\times10^{23}\)
\(N_{N_2O}=5.83\times10^{23}\space\text{molecules}\)

Answer:

For \(2.06\space mol\space C_2H_4\): \(1.24\times 10^{24}\space\text{molecules}\)
For \(0.968\space mol\space N_2O\): \(5.83\times 10^{23}\space\text{molecules}\)