Question

05 question (3 points) a precipitation reaction involves the formation of a precipitate when aqueous solutions are mixed. not all combinations of aqueous solutions produce precipitates, and it is important to be able to predict the ones that do. 1st attempt part 1 (1 point) complete and balance the molecular equation for the reaction between aqueous solutions of ammonium acetate and potassium sulfide, and use the states of matter to show if a precipitate forms. part 2 (1 point) write the complete ionic equation for the reaction that takes place when aqueous solutions of ammonium acetate and potassium sulfide are mixed. part 3 (1 point) write the net ionic equation for the precipitation reaction, if any, that may occur when aqueous solutions of ammonium acetate and

Explanation:

Step1: Write reactants and predict products

Ammonium acetate ($NH_4C_2H_3O_2$) and potassium sulfide ($K_2S$) react. Using double - displacement reaction rules, the products are ammonium sulfide ($(NH_4)_2S$) and potassium acetate ($KC_2H_3O_2$). The unbalanced molecular equation is $NH_4C_2H_3O_2(aq)+K_2S(aq)
ightarrow(NH_4)_2S(aq)+KC_2H_3O_2(aq)$.

Step2: Balance the molecular equation

By adjusting coefficients, the balanced molecular equation is $2NH_4C_2H_3O_2(aq)+K_2S(aq)
ightarrow(NH_4)_2S(aq)+2KC_2H_3O_2(aq)$. Since all products are soluble in water (ammonium and potassium salts are generally soluble), no precipitate forms.

Step3: Write the complete ionic equation

Break all aqueous compounds into ions. The complete ionic equation is $2NH_4^+(aq)+2C_2H_3O_2^-(aq)+2K^+(aq)+S^{2 - }(aq)
ightarrow2NH_4^+(aq)+S^{2 - }(aq)+2K^+(aq)+2C_2H_3O_2^-(aq)$.

Step4: Write the net ionic equation

Cancel out the spectator ions ($NH_4^+$, $C_2H_3O_2^-$, $K^+$, and $S^{2 - }$). The net ionic equation is no reaction, as all ions are spectator ions.

Answer:

Part 1: $2NH_4C_2H_3O_2(aq)+K_2S(aq)
ightarrow(NH_4)_2S(aq)+2KC_2H_3O_2(aq)$
Part 2: $2NH_4^+(aq)+2C_2H_3O_2^-(aq)+2K^+(aq)+S^{2 - }(aq)
ightarrow2NH_4^+(aq)+S^{2 - }(aq)+2K^+(aq)+2C_2H_3O_2^-(aq)$
Part 3: No reaction (all ions are spectator ions)