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yuto left his house at 10 a.m. to go for a bike ride. by the time yutos…

Question

yuto left his house at 10 a.m. to go for a bike ride. by the time yutos sister riko left their house, yuto was already 5.25 miles along the path they both took. if yutos average speed was 0.25 miles per minute and rikos average speed was 0.35 miles per minute, over what time period in minutes, (t), starting from when riko left the house, will riko be behind her brother?

riko will be behind yuto when (0 \le t <) minutes.

Explanation:

Formulate distance expressions

Using the Writing Linear Inequalities knowledge point

$$ LATEXBLOCK0 $$

Set up the inequality

Using the Writing Linear Inequalities knowledge point

$$ LATEXBLOCK1 $$

Solve the inequality

Using the Solving Linear Inequalities knowledge point

$$ LATEXBLOCK2 $$

Determine the time interval

Using the Solving Linear Inequalities knowledge point

$$ LATEXBLOCK3 $$

Answer:

Riko will be behind Yuto when \(0 \le t <\) <blank>\(52.5\)</blank> minutes.