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you be the teacher your friend solves the inequality \\frac{x}{3}+4 < 6…

Question

you be the teacher your friend solves the inequality
\frac{x}{3}+4 < 6
x + 4 < 18
x < 14
is your friend correct?
○ yes
○ no
explain your reasoning.

Explanation:

Step1: Analyze the first step

The original inequality is $\frac{x}{3}+4 < 6$. Subtract 4 from both sides: $\frac{x}{3}+4 - 4<6 - 4$, so $\frac{x}{3}<2$.

Step2: Analyze the second step

Multiply both sides by 3: $\frac{x}{3}\times3 < 2\times3$, which gives $x < 6$. But the friend's second step is $x + 4<18$ (wrong, should be $\frac{x}{3}<2$ after first step, not $x + 4<18$) and third step $x < 14$ (also wrong). So the friend made a mistake.

Answer:

no