Question

1. you made some cubes out of each metal in the table that each measures 2.00 cm on every side. (all except mercury - why cant you make a cube of mercury?) a. what is the volume of each cube in cm³? in ml? (show your thinking, work wisely) v = ____ cm³ v = __ ml b. find the mass of these metal cubes: (show your work below) lead cube ____ nickel cube ____ zinc cube ______

Explanation:

Step1: Calculate volume of cube

The volume formula for a cube is $V = s^3$, where $s$ is the side - length. Given $s = 2.00$ cm. So $V=(2.00\ cm)^3=8.00\ cm^3$.

Step2: Convert volume to mL

Since $1\ cm^3 = 1\ mL$, the volume in mL is also $8.00$ mL.

Step3: Calculate mass of lead cube

We need the density of lead. Let's assume the density of lead $
ho_{lead}=11.34\ g/cm^3$. Using the formula $m=
ho V$, with $V = 8.00\ cm^3$, then $m_{lead}=
ho_{lead}V=11.34\ g/cm^3\times8.00\ cm^3 = 90.72\ g$.

Step4: Calculate mass of nickel cube

Assume the density of nickel $
ho_{nickel}=8.908\ g/cm^3$. Using $m=
ho V$ with $V = 8.00\ cm^3$, then $m_{nickel}=
ho_{nickel}V=8.908\ g/cm^3\times8.00\ cm^3=71.264\ g$.

Step5: Calculate mass of zinc cube

Assume the density of zinc $
ho_{zinc}=7.14\ g/cm^3$. Using $m=
ho V$ with $V = 8.00\ cm^3$, then $m_{zinc}=
ho_{zinc}V=7.14\ g/cm^3\times8.00\ cm^3 = 57.12\ g$.

Answer:

a. $V = 8.00\ cm^3$, $V = 8.00\ mL$
b. lead cube: $90.72\ g$
nickel cube: $71.264\ g$
zinc cube: $57.12\ g$