Question

a yellow seeded, purple flowered heterozygous plant (yypp), is crossed with a green seeded, white flower plant (yypp). (y = yellow seed allele; y = green seed allele; p = purple flower allele; p = white flower allele)
what is the probability that an offspring of this cross produces plants with green seeds and white flower phenotypes? calculate the probabilities and complete the table. assume that the two genes sort independently of each other.
three boxes with 0.25, 0.75, 0.5
table with columns: offspring genotype, genotype probability (seeds shape, flower color), probability of offspring receiving the combined genotype; row: yypp with empty cells for probabilities

Explanation:

Step1: Analyze seed color inheritance

The cross for seed color is \(Yy\times yy\). The possible gametes from \(Yy\) are \(Y\) and \(y\), and from \(yy\) are \(y\) and \(y\). The Punnett square gives genotypes \(Yy\) and \(yy\) each with probability \(0.5\). For green seeds (\(yy\)), probability is \(0.5\).

Step2: Analyze flower color inheritance

The cross for flower color is \(Pp\times pp\). Gametes from \(Pp\) are \(P\) and \(p\), from \(pp\) are \(p\) and \(p\). Punnett square gives \(Pp\) and \(pp\) each with probability \(0.5\). For white flowers (\(pp\)), probability is \(0.5\).

Step3: Calculate combined probability

Since the genes assort independently, use the multiplication rule. Probability of \(yy\) (green seeds) is \(0.5\), probability of \(pp\) (white flowers) is \(0.5\). So combined probability is \(0.5\times0.5 = 0.25\). For the genotype \(yypp\), seed shape (color) probability is \(0.5\), flower color probability is \(0.5\), and combined is \(0.25\).

Answer:

For the table:

• Seeds shape (genotype \(yy\)) probability: \(0.5\)
• Flower color (genotype \(pp\)) probability: \(0.5\)
• Probability of \(yypp\): \(0.25\)

The probability of offspring with green seeds and white flowers is \(0.25\).