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δxyz at x(-6,1), y(4,0), z(1,3) is translated left 9 and up 12. what is…

Question

δxyz at x(-6,1), y(4,0), z(1,3) is translated left 9 and up 12. what is the new coordinate of x? (no spaces)

Explanation:

Step1: Translate the x - coordinate

For a translation left 9 units, subtract 9 from the x - coordinate.
The x - coordinate of \(X(-6,1)\) is \(-6\). After translation: \(-6-9=-15\)

Step2: Translate the y - coordinate

For a translation up 12 units, add 12 to the y - coordinate.
The y - coordinate of \(X(-6,1)\) is \(1\). After translation: \(1 + 12=13\)

Answer:

\((-15,13)\)