Question

1. write the following number as a decimal: 6.3×10⁻⁴
2. write the following number as a decimal: 9.2×10⁷
3. write the following number in scientific notation: 219,000,000
4. write the following number in scientific notation: 0.0000507
5. how is experimental uncertainty related to precision. if an instrument is listed to have an uncertainty of (±0.1 g) and another is (±0.001 g). which instrument is more precise?
6. explain how the law of conservation of energy applies to electrical production in a coal plant.
7. explain how the state of matter relates to the amount of energy a substance has.
8. determine which object has the greatest density.

object mass volume
#1 53.5 g 138 ml
#2 218 g 985 ml
#3 154 g 526 ml
c: the most dense object is _, it has a density of _.
e:(calculate density of each object. show work and include units)
object #1 object #2 object #3
r: since object _ has a density of _ compared to ......

Explanation:

Step1: Recall density formula

The density formula is $
ho=\frac{m}{V}$, where $
ho$ is density, $m$ is mass and $V$ is volume.

Step2: Calculate density of Object #1

For Object #1, $m = 53.5\ g$ and $V=138\ mL$. So $
ho_1=\frac{53.5\ g}{138\ mL}\approx 0.39\ g/mL$.

Step3: Calculate density of Object #2

For Object #2, $m = 218\ g$ and $V = 985\ mL$. So $
ho_2=\frac{218\ g}{985\ mL}\approx 0.22\ g/mL$.

Step4: Calculate density of Object #3

For Object #3, $m = 154\ g$ and $V = 526\ mL$. So $
ho_3=\frac{154\ g}{526\ mL}\approx 0.29\ g/mL$.

Step5: Compare densities

Comparing $
ho_1\approx 0.39\ g/mL$, $
ho_2\approx 0.22\ g/mL$ and $
ho_3\approx 0.29\ g/mL$, we find that Object #1 has the greatest density.

Answer:

The most dense object is #1, it has a density of approximately $0.39\ g/mL$.