QUESTION IMAGE
Question
write an expression in factored form for the polynomial
\\(y(x) =\\)
⚡ Using what you learned: Graphing Polynomial Functions
Step 1: Identify the roots and their multiplicities
Identify the \(x\)-intercepts (roots) from the graph and observe how the curve behaves at each intercept:
- At \(x = -4\), the graph crosses the \(x\)-axis directly. This indicates a root of multiplicity 1: factor \((x + 4)\).
- At \(x = -3\), the graph crosses the \(x\)-axis directly. This indicates a root of multiplicity 1: factor \((x + 3)\).
- At \(x = 1\), the graph touches the \(x\)-axis and turns around. This indicates a root of multiplicity 2: factor \((x - 1)^2\).
- At \(x = 3\), the graph crosses the \(x\)-axis directly. This indicates a root of multiplicity 1: factor \((x - 3)\).
The general factored form is:
$$ y(x) = a(x + 4)(x + 3)(x - 1)^2(x - 3) $$
Step 2: Find the leading coefficient \(a\)
Use the \(y\)-intercept from the graph, which is at \((0, -4.5)\) or \((0, -\frac{9}{2})\):
$$ y(0) = a(0 + 4)(0 + 3)(0 - 1)^2(0 - 3) = -4.5 $$
$$ a(4)(3)(1)(-3) = -4.5 $$
$$ -36a = -4.5 $$
$$ a = \frac{-4.5}{-36} = \frac{1}{8} $$
Step 3: Write the final expression
Substitute \(a = \frac{1}{8}\) back into the factored form:
$$ y(x) = \frac{1}{8}(x + 4)(x + 3)(x - 1)^2(x - 3) $$
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$$ y(x) = \frac{1}{8}(x + 4)(x + 3)(x - 1)^2(x - 3) $$