Question

write the expression \\(\frac{1}{2}(18y - 2y + 10)\\) as the sum of two unlike terms.

Explanation:

Step1: Simplify inside the parentheses

First, combine like terms inside the parentheses. We have \(18y - 2y+10\). Combining \(18y\) and \(-2y\) gives \(16y\), so the expression inside the parentheses becomes \(16y + 10\). So now our expression is \(\frac{1}{2}(16y + 10)\).

Step2: Distribute the \(\frac{1}{2}\)

Using the distributive property \(a(b + c)=ab+ac\), where \(a=\frac{1}{2}\), \(b = 16y\) and \(c = 10\). We get \(\frac{1}{2}\times16y+\frac{1}{2}\times10\).

Step3: Calculate each term

Calculating \(\frac{1}{2}\times16y\) gives \(8y\) and \(\frac{1}{2}\times10\) gives \(5\). So the expression as a sum of two unlike terms is \(8y + 5\).

Answer:

\(8y + 5\)