Question

write an equation in slope - intercept form for a line that has a slope, $m = 2$, and passes through the point $(3,-4)$. (hint: write the equation in point - slope form first and then solve for y.)
$y = 2x - 10$
$y = 2x + 10$
$y = 2x - 1$
$y = 2x - 4$

Explanation:

Step1: Write point - slope form

The point - slope form of a line is $y - y_1=m(x - x_1)$, where $m$ is the slope and $(x_1,y_1)$ is a point on the line. Given $m = 2$, $x_1=3$ and $y_1=-4$, we have $y-(-4)=2(x - 3)$.

Step2: Simplify the equation

$y + 4=2x-6$.

Step3: Solve for y

Subtract 4 from both sides: $y=2x-6 - 4$, so $y = 2x-10$.

Answer:

$y = 2x-10$