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write an equation in slope-intercept form for the line with slope -4 an…

Question

write an equation in slope-intercept form for the line with slope -4 and y-intercept -1. then graph the line.
equation:
(there is a coordinate grid on the right side of the equation input area.)

Explanation:

Step1: Recall slope-intercept form

The slope-intercept form of a line is $y = mx + b$, where $m$ is the slope and $b$ is the y-intercept.

Step2: Substitute given values

Substitute $m = -4$ and $b = -1$ into the formula:
$y = -4x + (-1)$ which simplifies to $y = -4x - 1$.

Step3: Identify points for graphing

  • Y-intercept point: When $x=0$, $y=-1$, so the point is $(0, -1)$.
  • Second point using slope: Slope $\frac{\Delta y}{\Delta x} = \frac{-4}{1}$, so from $(0, -1)$, move 1 unit right and 4 units down to get $(1, -5)$.

Answer:

Equation: $\boldsymbol{y = -4x - 1}$
To graph the line:

  1. Plot the y-intercept point $(0, -1)$ on the coordinate plane.
  2. Plot the second point $(1, -5)$.
  3. Draw a straight line passing through these two points, extending it across the entire grid.