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write the equation in slope-intercept form. -10x + 2y = 12

Question

write the equation in slope-intercept form.
-10x + 2y = 12

Explanation:

Step1: Isolate the y-term

We start with the equation \(-10x + 2y = 12\). To isolate the term with \(y\), we add \(10x\) to both sides of the equation.

$$ -10x + 2y + 10x = 12 + 10x $$

Simplifying the left side, the \(-10x\) and \(+10x\) cancel out, leaving us with:

$$ 2y = 10x + 12 $$

Step2: Solve for y

Now, we want to solve for \(y\), so we divide every term in the equation by \(2\) (the coefficient of \(y\)).

$$ \frac{2y}{2}=\frac{10x}{2}+\frac{12}{2} $$

Simplifying each term, we get:

$$ y = 5x + 6 $$

Answer:

\(y = 5x + 6\)