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write the coordinates of the vertices after a rotation 180° countercloc…

Question

write the coordinates of the vertices after a rotation 180° counterclockwise around the origin.

Explanation:

Step1: Identify Original Vertices

First, find the coordinates of the original vertices. From the graph:

  • Vertex \( P \): Let's assume the original \( P \) is \( (-5, -1) \)? Wait, no, looking at the grid, let's re - check. Wait, the original vertices (let's name them as \( P \), \( Q \), \( R \)): Let's see, one vertex is at \( (-5, -1) \)? Wait, no, maybe the original vertices are: Let's look at the graph again. Wait, the triangle has vertices: Let's say \( P(-5, -1) \)? No, maybe the original vertices are: Let's find the coordinates. Let's take the bottom - left vertex as \( P(-5, -9) \)? No, maybe I misread. Wait, the rotation rule for \( 180^{\circ} \) counterclockwise (or clockwise, since \( 180^{\circ} \) rotation is the same in both directions) around the origin is \( (x,y)\to(-x, -y) \).

Wait, let's correctly identify the original vertices. Let's assume the three vertices are:

  • Let's call the top - left vertex \( A(-5, -1) \)? No, looking at the grid, let's see the coordinates. Let's take the vertices as:
  • Vertex 1: Let's say \( (-5, -1) \)? Wait, no, maybe the original vertices are \( (-5, -1) \), \( (-5, -9) \), and \( (-1, -10) \)? Wait, no, let's do it properly. Let's look at the graph:

Wait, the first vertex (let's call it \( P \)): Let's find its \( x \) and \( y \) coordinates. If we look at the grid, the \( x \) - coordinate is - 5 (since it's 5 units to the left of the origin on the \( x \) - axis) and \( y \) - coordinate is - 1 (1 unit below the \( x \) - axis)? No, maybe the \( y \) - coordinate is - 1? Wait, no, the grid lines: Let's assume each grid square is 1 unit. So, let's find the three vertices:

  1. Let's take the vertex at \( (-5, -1) \) (let's call it \( P \))
  2. The vertex at \( (-5, -9) \) (let's call it \( Q \))
  3. The vertex at \( (-1, -10) \) (let's call it \( R \))

Wait, no, maybe the original vertices are \( (-5, -1) \), \( (-5, -9) \), and \( ( - 1,-10) \)? Wait, no, let's use the rotation rule. The rule for a \( 180^{\circ} \) rotation about the origin is \( (x,y)\to(-x, -y) \).

Wait, maybe the original vertices are:

  • Let's say the three vertices are \( (-5, -1) \), \( (-5, -9) \), and \( ( - 1,-10) \). Then after rotation:
  • For \( (-5, -1) \): \( (-(-5),-(-1))=(5,1) \)
  • For \( (-5, -9) \): \( (-(-5),-(-9))=(5,9) \)
  • For \( (-1, -10) \): \( (-(-1),-(-10))=(1,10) \)

But maybe I misidentified the original vertices. Wait, let's look at the graph again. Let's assume the three vertices are:

  • Vertex \( A(-5, -1) \)
  • Vertex \( B(-5, -9) \)
  • Vertex \( C(-1, -10) \)

After \( 180^{\circ} \) rotation around the origin, the new coordinates are:

Step1: Identify Original Coordinates

Let's correctly identify the original vertices from the graph:

  • Let's take the first vertex (top - left) as \( (-5, -1) \) (so \( x=-5,y = - 1\))
  • The second vertex (bottom - left) as \( (-5, -9) \) (so \( x = - 5,y=-9\))
  • The third vertex (bottom - right) as \( (-1, -10) \) (so \( x=-1,y = - 10\))

Step2: Apply \( 180^{\circ} \) Rotation Rule

The rule for a \( 180^{\circ} \) rotation about the origin is \( (x,y)\to(-x,-y) \)

  • For the first vertex \( (-5, -1) \):
  • New \( x=-(-5) = 5 \)
  • New \( y=-(-1)=1 \)
  • So the new coordinate is \( (5,1) \)
  • For the second vertex \( (-5, -9) \):
  • New \( x=-(-5)=5 \)
  • New \( y=-(-9) = 9 \)
  • So the new coordinate is \( (5,9) \)
  • For the third vertex \( (-1, -10) \):
  • New \( x=-(-1)=1 \)
  • New \( y=-(-10)=10 \)
  • So the new coordinate is \( (1,10) \)

Wait, maybe I made a mistake in identifying the original coordinates. Let's re - c…

Answer:

If the original vertices are \( (-5, -1) \), \( (-5, -9) \), \( (-1, -10) \), the new vertices after \( 180^{\circ} \) rotation are \( (5,1) \), \( (5,9) \), \( (1,10) \)

(Note: The exact coordinates depend on the correct identification of the original vertices from the graph. The key step is applying the \( 180^{\circ} \) rotation rule \( (x,y)\to(-x,-y) \))