Question

which is true for an object in free - fall? it has a constant displacement. it increases in distance proportionally to t². it has frictional effects. it has a constant velocity. submit answer. - / 4 points how are position and motion related?

Explanation:

• For an object in free - fall, the displacement formula is \(s = v_0t+\frac{1}{2}gt^{2}\). If the object is dropped from rest (\(v_0 = 0\)), then \(s=\frac{1}{2}gt^{2}\), which means the distance \(s\) is proportional to \(t^{2}\).
• Constant displacement would imply zero acceleration, which is not the case for free - fall (\(a = g

eq0\)).

• In free - fall, we assume no frictional effects (air resistance is neglected).
• Constant velocity implies zero acceleration, but in free - fall \(a = g

eq0\).

Answer:

It increases in distance proportionally to \(t^{2}\).