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Question
which trig function would you use to solve for x? 20 55° x sine tangent cosine secant
Step1: Recall trigonometric ratios
In a right - triangle, \(\sin\theta=\frac{\text{opposite}}{\text{hypotenuse}}\), \(\cos\theta=\frac{\text{adjacent}}{\text{hypotenuse}}\), \(\tan\theta=\frac{\text{opposite}}{\text{adjacent}}\), \(\sec\theta=\frac{\text{hypotenuse}}{\text{adjacent}}\).
Here, the hypotenuse is \(20\), the adjacent side to the \(55^{\circ}\) angle is \(x\).
Step2: Match the ratio
Since we have the hypotenuse and the adjacent side, \(\cos\theta=\frac{\text{adjacent}}{\text{hypotenuse}}\). So \(\cos(55^{\circ})=\frac{x}{20}\).
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