Question

at which temperature does water have particles with a greater average kinetic energy than water with a temperature of 30°c?
77°f
95°f
280k
300k

Explanation:

Step1: Convert temperatures to Celsius

• For \(77^{\circ}F\):

Use the formula \(T_{C}=\frac{5}{9}(T_{F}- 32)\).
\(T_{C}=\frac{5}{9}(77 - 32)=\frac{5}{9}\times45 = 25^{\circ}C\)

• For \(95^{\circ}F\):

\(T_{C}=\frac{5}{9}(95 - 32)=\frac{5}{9}\times63=35^{\circ}C\)

• For \(280K\):

Use the formula \(T_{C}=T_{K}-273\).
\(T_{C}=280 - 273=7^{\circ}C\)

• For \(300K\):

\(T_{C}=300 - 273 = 27^{\circ}C\)

Step2: Compare with \(30^{\circ}C\)

We want a temperature greater than \(30^{\circ}C\). Among the converted temperatures (\(25^{\circ}C\), \(35^{\circ}C\), \(7^{\circ}C\), \(27^{\circ}C\)), only \(35^{\circ}C\) (from \(95^{\circ}F\)) is greater than \(30^{\circ}C\)

Answer:

\(95^{\circ}F\)