Question

which shows the difference (\frac{p^{2}+6p + 2}{4p^{2}}-\frac{10p^{2}}{4p^{2}})? (\frac{-3p^{2}+2}{4p^{2}}) (\frac{-9p^{2}+6p + 2}{4p^{2}}) (\frac{11p^{2}+6p + 2}{4p^{2}}) (\frac{-9p^{2}-4p - 8}{4p^{2}})

Explanation:

Step1: Subtract numerators directly

Since the fractions have the same denominator, subtract the numerators while keeping the denominator unchanged.
$\frac{p^2+6p+2}{4p^2} - \frac{10p^2}{4p^2} = \frac{(p^2+6p+2) - 10p^2}{4p^2}$

Step2: Combine like terms in numerator

Simplify the terms in the numerator by combining $p^2$ terms.
$\frac{p^2 - 10p^2 + 6p + 2}{4p^2} = \frac{-9p^2 + 6p + 2}{4p^2}$

Answer:

$\frac{-9p^2+6p+2}{4p^2}$