QUESTION IMAGE
Question
- which relationship is a direct variation?
f
| x | 1 | 2 | 3 | 4 |
| y | -1 | 0 | 1 | 2 |
g
| x | 1 | 2 | 3 | 4 |
| y | 0 | -1 | -2 | -3 |
h
| x | 1 | 2 | 3 | 4 |
| y | 3 | 5 | 7 | 9 |
j
| x | 1 | 2 | 3 | 4 |
| y | 3 | 6 | 9 | 12 |
Step1: Recall Direct Variation
Direct variation has the form \( y = kx \), so \( \frac{y}{x}=k \) (constant) for all \( x
eq0 \).
Step2: Check Option F
For F: \( \frac{-1}{1}=-1 \), \( \frac{0}{2}=0 \). Not constant. Reject.
Step3: Check Option G
For G: \( \frac{0}{1}=0 \), \( \frac{-1}{2}=-0.5 \). Not constant. Reject.
Step4: Check Option H
For H: \( \frac{3}{1}=3 \), \( \frac{5}{2}=2.5 \). Not constant. Reject.
Step5: Check Option J
For J: \( \frac{3}{1}=3 \), \( \frac{6}{2}=3 \), \( \frac{9}{3}=3 \), \( \frac{12}{4}=3 \). Constant \( k = 3 \).
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J. \( \boldsymbol{x}\): 1, 2, 3, 4; \( \boldsymbol{y}\): 3, 6, 9, 12