Question

which of the following options best completes the column for!(x||x) in the truth table? x y!(x||x)!x&&!y!(x||x)||(!x&&!y) t t f t f ? f t f f false true

Explanation:

Step1: Evaluate \(x || x\) when \(x=T\)

\(T || T = T\)

Step2: Negate the result

\(!T = F\)

Answer:

False