Question

which of the following options best completes the column for!(x||x) in the truth table?

x y!(x||x)!x &&!y!(x||x) || (!x &&!y)
t t f
t f f
f t ?
f f

Explanation:

Step1: Evaluate x || x when x=F

$F || F = F$

Step2: Negate the result

$!(F) = T$

Answer:

True