Question

which of the following options best completes the column for (y && y) || (x &&!x) in the truth table? x y (y && y) (x &&!x) (y && y) || (x &&!x) t t t t f f f t t f f ? false true

Explanation:

Step1: Analyze (y && y)

For logical AND (&&), if \( y = F \), then \( y\ &&\ y=F\ &&\ F = F \).

Step2: Analyze (x &&!x)

For logical NOT (!), if \( x = F \), then \(!x = T \). But \( x\ &&\!x=F\ &&\ T = F \).

Step3: Analyze (y && y) || (x &&!x)

For logical OR (||), if both operands are \( F \) (from Step1 and Step2: \( F||F \)), the result is \( F \).

Answer:

False