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Question
which explains whether △fgh is congruent to △fjh? they are not congruent because only one pair of corresponding sides is congruent. they are congruent because opposite sides of a parallelogram are congruent. they are congruent because \\(\overline{gh} \cong \overline{gf}\\), \\(\overline{jf} \cong \overline{jh}\\), and \\(\overline{fh} \cong \overline{fh}\\) they are not congruent because only two pairs of corresponding sides are congruent.
Step1: Analyze the figure
From the diagram, we can see that \( GF \cong JH \) (single tick marks), \( JF \cong JH \)? Wait, no, \( JF \) and \( JH \) have double tick marks? Wait, looking at the figure: \( GF \) and \( JH \) have single tick marks (so \( GF \cong JH \)), \( JF \) and \( JH \)? Wait, no, \( JF \) and \( JH \)? Wait, the sides \( JF \) and \( JH \)? Wait, actually, \( JF \) and \( JH \) – no, looking at the figure, \( JF \) and \( JH \)? Wait, the quadrilateral: \( FJ \) and \( JH \)? Wait, no, the triangles are \( \triangle FGH \) and \( \triangle FJH \). Let's check the sides:
- \( GF \cong JH \) (single tick marks)
- \( JF \cong JH \)? Wait, no, \( JF \) and \( JH \) – wait, \( JF \) and \( JH \) have double tick marks? Wait, the side \( FJ \) and \( JH \)? Wait, no, the side \( FJ \) and \( JH \) – actually, \( FJ \) and \( JH \) – wait, the common side is \( FH \). So for \( \triangle FGH \) and \( \triangle FJH \):
- \( GF \cong JH \) (given by single tick)
- \( JF \cong GH \)? Wait, no, the double tick marks: \( FJ \) and \( JH \)? Wait, no, the double tick marks are on \( FJ \) and \( JH \)? Wait, the figure: \( FJ \) has double tick, \( JH \) has double tick? Wait, no, the side \( FJ \) and \( JH \) – wait, the quadrilateral: \( FJ \) and \( JH \) are equal (double tick), \( GF \) and \( JH \) – no, \( GF \) and \( GH \)? Wait, maybe I misread. Let's re-examine:
The triangles are \( \triangle FGH \) and \( \triangle FJH \). Let's list the sides:
- \( GF \) and \( JH \): single tick, so \( GF \cong JH \)
- \( FJ \) and \( GH \): wait, no, \( FJ \) has double tick, \( JH \) has double tick? Wait, the side \( FJ \) and \( JH \) – no, the side \( FJ \) and \( JH \) are equal (double tick), and \( GF \) and \( GH \) – no, \( GF \) has single tick, \( GH \) has single tick? Wait, no, the single tick is on \( GF \) and \( GH \)? Wait, no, the figure: \( GF \) (top side) has single tick, \( GH \) (right side) has single tick? No, the right side \( GH \) has single tick, top side \( GF \) has single tick? Wait, no, the left side \( FJ \) has double tick, bottom side \( JH \) has double tick. So:
For \( \triangle FGH \) and \( \triangle FJH \):
- \( GF \cong JH \) (single tick)
- \( JF \cong GH \) (double tick? Wait, no, \( FJ \) and \( GH \) – no, \( FJ \) has double tick, \( GH \) has single tick? Wait, I think I made a mistake. Let's look at the third option: "They are congruent because \( \overline{GH} \cong \overline{GF} \), \( \overline{JF} \cong \overline{JH} \), and \( \overline{FH} \cong \overline{FH} \)". Wait, no, the third option says \( \overline{GH} \cong \overline{GF} \), \( \overline{JF} \cong \overline{JH} \), and \( \overline{FH} \cong \overline{FH} \). Wait, but that would be SSS? Wait, no, \( \overline{GH} \cong \overline{GF} \) – is that true? Wait, the single tick marks: \( GF \) and \( GH \) – no, the single tick is on \( GF \) and \( JH \). Wait, maybe the correct approach is:
The triangles \( \triangle FGH \) and \( \triangle FJH \):
- \( GF \cong JH \) (single tick)
- \( JF \cong GH \) (double tick? Wait, no, \( FJ \) and \( GH \) – no, \( FJ \) has double tick, \( JH \) has double tick. Wait, the common side is \( FH \), so \( FH \cong FH \) (reflexive property). So if we have:
- \( GF \cong JH \)
- \( JF \cong GH \)
- \( FH \cong FH \)
Then by SSS, the triangles are congruent. Wait, but the third option says \( \overline{GH} \cong \overline{GF} \), \( \overline{JF} \cong \overline{JH} \), and \( \overline{FH} \cong \overline{FH} \). Wait, maybe that's a typo, but let's check the…
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The third option (bottom - left) which states "They are congruent because \( \overline{GH} \cong \overline{GF} \), \( \overline{JF} \cong \overline{JH} \), and \( \overline{FH} \cong \overline{FH} \)".