Question

which equation can be used to find x, the length of the hypotenuse of the right triangle? (16 + 63)^2 = x^2 16 + 63 = x 16^2 + 63^2 = x^2 16^2 + 63 = x

Explanation:

Step1: Recall Pythagorean theorem

For a right - triangle with legs \(a\) and \(b\) and hypotenuse \(c\), the formula is \(a^{2}+b^{2}=c^{2}\). Here \(a = 16\), \(b = 63\), and \(c=x\).

Step2: Substitute values into the formula

Substitute \(a = 16\) and \(b = 63\) into \(a^{2}+b^{2}=c^{2}\). We get \(16^{2}+63^{2}=x^{2}\).

Answer:

\(16^{2}+63^{2}=x^{2}\)