Question

which is a counterexample for the conditional statement? if a square has side length s, then the perimeter is less than the area. s = 3 s = 5 s = 7 s = 9

Explanation:

Step1: Calculate perimeter and area for \(s = 3\)

Perimeter of square \(P=4s\), so \(P = 4\times3=12\). Area of square \(A=s^{2}\), so \(A = 3^{2}=9\). Here \(P>A\) (since \(12>9\)).

Step2: Calculate perimeter and area for \(s = 5\)

Perimeter \(P = 4\times5 = 20\). Area \(A=5^{2}=25\). Here \(P

Step3: Calculate perimeter and area for \(s = 7\)

Perimeter \(P=4\times7 = 28\). Area \(A = 7^{2}=49\). Here \(P

Step4: Calculate perimeter and area for \(s = 9\)

Perimeter \(P=4\times9=36\). Area \(A=9^{2}=81\). Here \(P

Answer:

\(s = 3\)