Question

which of the choices represents a solution of the equation?
$2x^2 - 6x = 0$
click on the correct answer.
$\frac{6 + sqrt{36}}{2(2)}$
$\frac{6 + sqrt{36 - 4(2)(-6)}}{2(2)}$
$\frac{6 + sqrt{36 - 4(2)(1)}}{2(2)}$

Explanation:

Step1: Recall quadratic formula

For $ax^2+bx+c=0$, solutions are $x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

Step2: Identify a, b, c

Given $2x^2-6x=0$, so $a=2$, $b=-6$, $c=0$

Step3: Substitute into formula (plus root)

$x=\frac{-(-6)+\sqrt{(-6)^2-4(2)(0)}}{2(2)}=\frac{6+\sqrt{36}}{2(2)}$

Answer:

$\boldsymbol{\frac{6 + \sqrt{36}}{2(2)}}$