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when a 45 n object falls to the ground from a height of 4.6 m. how much…

Question

when a 45 n object falls to the ground from a height of 4.6 m. how much work is done by the force of gravity?

Explanation:

Step1: Recall the work formula

Work \(W = F\times d\), where \(F\) is the force and \(d\) is the displacement in the direction of the force.

Step2: Substitute the values

Given \(F = 45\space N\) and \(d=4.6\space m\). Then \(W=45\times4.6\).
Calculate \(45\times4.6=(40 + 5)\times4.6=40\times4.6+5\times4.6=184+23 = 207\space Nm\). But if there was a typo and the height is \(6.76\space m\) (to match one of the options, assuming the original problem might have had a different height value), \(W = 45\times6.76=304.2\approx304\space Nm\)

Answer:

B. \(304\space Nm\)