Question

1. what are the zeros of $x^2 - 6x + 5 = 0$?

a. $x = 1$ and $x = 5$
b. $x = -1$ and $x = -5$
c. $x = 1$ and $x = -5$
d. $x = -1$ and $x = 5$

Explanation:

Step1: Factor the quadratic equation

To find the zeros of \(x^2 - 6x + 5 = 0\), we factor the quadratic. We need two numbers that multiply to \(5\) and add to \(-6\). The numbers are \(-1\) and \(-5\), so the equation factors as \((x - 1)(x - 5)=0\).

Step2: Solve for \(x\)

Set each factor equal to zero: \(x - 1 = 0\) or \(x - 5 = 0\). Solving these gives \(x = 1\) or \(x = 5\).

Answer:

A. \(x = 1\) and \(x = 5\)