Question

1. what is the weight (in newtons) of a person with a mass of 95.0 kg?

a. 9.70 n
b. 105 n
c. 95.0 n
d. 931 n

1. an object has 16 n of force being applied to the right, 16 n of force being applied to the left, and 4 n of force being applied downward. what is the net force on the object?

a. 36 n
b. 32 n
c. 4 n downward
d. 16 n to the left

1. a 700.0 kg car is driving with an acceleration of 5.0 m/s² down the interstate. what is the force required to accelerate the car?

a. 3,500 n
b. 14 n
c. 650 n
d. 0.071 n

Explanation:

Question 8

Step1: Recall the formula for weight

Weight \(W = m\times g\), where \(m\) is mass and \(g = 9.8\ m/s^{2}\)

Step2: Substitute the values

Given \(m=95.0\ kg\), then \(W=95.0\times9.8\)

$$W = 95.0\times9.8=931\ N$$

Step1: Analyze horizontal forces

Forces to the right \(F_{r}=16\ N\) and to the left \(F_{l}=16\ N\). Net horizontal force \(F_{h}=F_{r}-F_{l}=16 - 16=0\ N\)

Step2: Analyze vertical force

Vertical force \(F_{v}=4\ N\) (downward). Since horizontal net force is \(0\), net force is the vertical force.

Step1: Use Newton's second law

Newton's second law \(F = m\times a\), where \(m = 700.0\ kg\) and \(a=5.0\ m/s^{2}\)

Step2: Calculate the force

\(F=700.0\times5.0\)

$$F = 700.0\times5.0=3500\ N$$

Answer:

D. \(931\ N\)

Question 9