Question

what is the volume of a sphere with a radius of 6.9 ft, rounded to the nearest tenth of a cubic foot? answer attempt 1 out of 2 ft³ submit answer

Explanation:

Step1: Write the formula for the volume of a sphere

The formula for the volume \(V\) of a sphere is \(V=\frac{4}{3}\pi r^{3}\), where \(r\) is the radius of the sphere.

Step2: Substitute the given radius into the formula

Given \(r = 6.9\) ft. Then \(V=\frac{4}{3}\pi(6.9)^{3}\).
First, calculate \((6.9)^{3}=6.9\times6.9\times6.9 = 328.509\).
Then \(V=\frac{4}{3}\pi\times328.509\).
\(\frac{4}{3}\times328.509 = 438.012\).
So \(V = 438.012\pi\).
Using \(\pi\approx3.14\), we have \(V\approx438.012\times3.14=1375.35768\).

Step3: Round the result to the nearest tenth

Rounding \(1375.35768\) to the nearest tenth. The digit in the hundredth place is \(5\), so we round up the digit in the tenth place.

Answer:

\(1375.4\)