Question

what is the volume of a cone with radius of 5 inches and height of 3 inches? move the correct answer to each box. not all answers will be used. $\frac{1}{3}\pi$ 3 $15\pi$ 9 $25\pi$ 5 $v =$ in.$^{3}=$ in.$^{3}$

Explanation:

Step1: Recall the volume formula of a cone

The volume formula of a cone is \(V=\frac{1}{3}\pi r^{2}h\). Here, \(r = 5\) inches and \(h=3\) inches.

Step2: Substitute the values into the formula

Substitute \(r = 5\) and \(h = 3\) into \(V=\frac{1}{3}\pi r^{2}h\). We get \(V=\frac{1}{3}\pi\times5^{2}\times3\).

Step3: Simplify the expression

First, calculate \(5^{2}=25\). Then \(\frac{1}{3}\times3 = 1\). So \(V = 25\pi\) cubic inches.

Answer:

\(V=\frac{1}{3}\pi\times5^{2}\times3\) in.\(^{3}=25\pi\) in.\(^{3}\)